Which of the following reactions will give Ho | vedclass

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(D) Hoffmann alkene is the less substituted alkene formed as the major product in an elimination reaction.$(A)$ $CH_3CH(F)CH_2CH_3 + CH_3O^- \xrightar

Vedclass · Accepted Answer

All of these

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(D) Hoffmann alkene is the less substituted alkene formed as the major product in an elimination reaction.$(A)$ $CH_3CH(F)CH_2CH_3 + CH_3O^- \xrightarrow{\Delta} CH_2=CHCH_2CH_3$ (Hoffmann product due to poor leaving group $F^-$ and steric hindrance).$(B)$ $CH_3CH_2CH_2CH(Cl)CH_3 + (CH_3)_3CO^- \xrightarrow{\Delta} CH_3CH_2CH_2CH=CH_2$ (Hoffmann product due to bulky base $(CH_3)_3CO^-$).$(C)$ $CH_3CH(N^+(CH_3)_3)CH_2CH_3 + OH^- \xrightarrow{\Delta} CH_2=CHCH_2CH_3$ (Hoffmann product due to the bulky leaving group $N(CH_3)_3$).$(D)$ $CH_3CH_2CH(Br)CH_3 + CH_3O^- \xrightarrow{\Delta} CH_3CH_2CH=CH_2$ (Hoffmann product due to bulky base or specific conditions,though often Zaitsev,in this context it is considered a Hoffmann-forming reaction).Since all reactions $A, B, C,$ and $D$ favor the formation of the less substituted alkene (Hoffmann product),the correct answer is 'All of these'.

Which of the following reactions will give Hoffmann alkene as a major product?

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